62 lines
1.6 KiB
TypeScript
62 lines
1.6 KiB
TypeScript
import * as T from "../types";
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/**
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* returns the singular and plural english word for a Pashto entry if possible
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* NOTE: only works with nouns and adjectives
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*
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* @param entry dictionary entry
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* @returns undefined if not possible, string for adjective, { singular?: string, plural: string } for noun
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*/
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export function getEnglishWord(entry: T.DictionaryEntry): {
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singular?: string,
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plural: string,
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} | string | undefined {
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if (!entry.c) return undefined;
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const isNoun = entry.c.includes("n.");
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const isAdj = entry.c.includes("adj.");
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if (!isNoun && !isAdj) return undefined;
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const base = entry.e.split(",")[0].split(";")[0].split("(")[0].trim();
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if (isAdj && !isNoun) {
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return base;
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}
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if (entry.ec && entry.ep) {
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return {
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singular: entry.ec,
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plural: entry.ep,
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};
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}
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if (entry.c.includes("pl.")) {
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return {
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plural: base,
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};
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}
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if (base.slice(-3) === "sis") {
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return {
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singular: base,
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plural: `${base.slice(0, -2)}es`,
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};
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}
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if (
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["sh", "ch"].includes(base.slice(-2)) ||
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["s", "x", "z", "o"].includes(base.slice(-1))
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) {
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return {
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singular: base,
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plural: `${base}es`,
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};
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}
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if (base.slice(-1) === "y" && !isVowel(base.slice(-2, -1))) {
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return {
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singular: base,
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plural: `${base.slice(0, -1)}ies`,
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};
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}
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return {
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singular: base,
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plural: `${base}s`,
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};
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}
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function isVowel(l: string): boolean {
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return ["a", "e", "i", "o", "u"].includes(l);
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} |